Tidy data

Pivoting

long to wide

table4a_long <- table4a %>%
    
    pivot_longer(cols = c('1999', '2000'), 
                 names_to = "year",
                 values_to = "cases" )

wide to long form

table4a_long %>%
    
    pivot_wider(names_from = year,
                values_from = cases)
## # A tibble: 3 × 3
##   country     `1999` `2000`
##   <chr>        <dbl>  <dbl>
## 1 Afghanistan    745   2666
## 2 Brazil       37737  80488
## 3 China       212258 213766

Separating and Uniting

Seperate a column

table3_sep <- table3 %>%
    
    separate(col = rate, into = c("cases", "population"))

Unite two columns

table3_sep %>%
    
    unite(col = "rate", cases:population, sep = "/", )
## # A tibble: 6 × 3
##   country      year rate             
##   <chr>       <dbl> <chr>            
## 1 Afghanistan  1999 745/19987071     
## 2 Afghanistan  2000 2666/20595360    
## 3 Brazil       1999 37737/172006362  
## 4 Brazil       2000 80488/174504898  
## 5 China        1999 212258/1272915272
## 6 China        2000 213766/1280428583
table3_sep %>%
    
    unite(col = "rate", c(cases,population), sep = "/")
## # A tibble: 6 × 3
##   country      year rate             
##   <chr>       <dbl> <chr>            
## 1 Afghanistan  1999 745/19987071     
## 2 Afghanistan  2000 2666/20595360    
## 3 Brazil       1999 37737/172006362  
## 4 Brazil       2000 80488/174504898  
## 5 China        1999 212258/1272915272
## 6 China        2000 213766/1280428583

Missing Values

stocks <- tibble(
    year = c(2015, 2015, 2015, 2015, 2016, 2016, 2016),
    qtr = c (1, 2, 3, 4, 2, 3, 4),
    return = c(1.88, 0.59, 0.35, NA, 0.92, 0.17, 2.66)
    )
stocks %>%
    
    pivot_wider(names_from = year, values_from = return)
## # A tibble: 4 × 3
##     qtr `2015` `2016`
##   <dbl>  <dbl>  <dbl>
## 1     1   1.88  NA   
## 2     2   0.59   0.92
## 3     3   0.35   0.17
## 4     4  NA      2.66
stocks %>%
    
    complete(year, qtr)
## # A tibble: 8 × 3
##    year   qtr return
##   <dbl> <dbl>  <dbl>
## 1  2015     1   1.88
## 2  2015     2   0.59
## 3  2015     3   0.35
## 4  2015     4  NA   
## 5  2016     1  NA   
## 6  2016     2   0.92
## 7  2016     3   0.17
## 8  2016     4   2.66
treatment <- tribble(
    ~ person,      ~ treatment, ~response,
    "Derrick Whitmore", 1,       7,
    NA,                 2,      10,
    NA,                 3,       9,
    "Katherine Burke",  1,       4
)

treatment %>%
    
    fill(person, .direction = "down")
## # A tibble: 4 × 3
##   person           treatment response
##   <chr>                <dbl>    <dbl>
## 1 Derrick Whitmore         1        7
## 2 Derrick Whitmore         2       10
## 3 Derrick Whitmore         3        9
## 4 Katherine Burke          1        4

Non-Tidy Data