getwd()
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# List of packages
packages <- c("tidyverse", "infer", "fst", "modelsummary", "effects", "survey", "interactions", "broom") # add any you need here

# Install packages if they aren't installed already
new_packages <- packages[!(packages %in% installed.packages()[,"Package"])]
if(length(new_packages)) install.packages(new_packages)

# Load the packages
lapply(packages, library, character.only = TRUE)
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Task 1

Graph the histogram distribution using the populist scale (as we did in the tutorial) for the country of Sweden. What do you note?

sweden_data <- read.fst("sweden_data.fst")
# Populist scale (Norris/Inglehart use low levels of trust in parliaments, politicians and parties as an indicator of populism)

# Note: Schafer does it 2 ways, we will focus now on the most straightforward

# Setting values greater than 10 to NA
sweden_data$trstplt <- ifelse(sweden_data$trstplt > 10, NA, sweden_data$trstplt)
sweden_data$trstprl <- ifelse(sweden_data$trstprl > 10, NA, sweden_data$trstprl)
sweden_data$trstprt <- ifelse(sweden_data$trstprt > 10, NA, sweden_data$trstprt)

# Creating and rescaling the trust variable
sweden_data$trust <- scales::rescale(sweden_data$trstplt + sweden_data$trstprl + sweden_data$trstprt, na.rm = TRUE, to = c(0, 100))

# Here's how you would "flip it" because populist is conceived by N + I as 'anti-trust'
# As Schafer explains there are some issues with that conceptualization, but N + I is also widely applied
sweden_data$populist <- scales::rescale(sweden_data$trust, na.rm = TRUE, to=c(100,0))
ggplot(sweden_data, aes(x = populist)) +
  geom_histogram(bins = 30, fill = "blue", color = "black") +
  theme_minimal() +
  labs(title = "Distribution of Populist Scale for Sweden",
       x = "Populist Scale",
       y = "Count")
## Warning: Removed 2503 rows containing non-finite outside the scale range
## (`stat_bin()`).

The histogram shows that the distribution of the populist scale for the country of Sweden. The Vertical axis is represent the count of the range. The horizontal axis is represent the populist scale of Sweden. It looks like normal distribution. This histogram is the right skewed. There is a highest number near 50. Other number is around 50.

Task 2

Run a linear regression with populist attitudes as the outcome, educational attainment (recoded as a binary “BA or more” and “No BA”), and using the Swedish data. Print the intercept and coefficients only and interpret. Then do a tidy model table displaying the p-value (with digits = 3) and interpret.

sweden_data_lr <- sweden_data |>
  mutate(
    educ.ba = case_when(
      essround < 5 & edulvla == 5 ~ "BA or more",
      essround >= 5 & edulvlb > 600 ~ "BA or more",
      TRUE ~ "No BA"
    ) ) |>
  # Cleaning NA's
  mutate(
    edulvla = ifelse(edulvla %in% c(77, 88), NA_integer_, edulvla),
    edulvlb = ifelse(edulvlb %in% c(5555, 7777, 8888), NA_integer_, edulvlb),
    educ.ba = as.character(educ.ba)  # Force educ.ba to be treated as character
  )
sweden_pop_model <- lm(populist ~ educ.ba, data = sweden_data_lr) # populism = dependent (outcome), educ.ba = independent (explanatory)
coefficients_sweden <- coef(sweden_pop_model)
print(coefficients_sweden)
##  (Intercept) educ.baNo BA 
##    43.490559     7.868121
tidy(sweden_pop_model) 
## # A tibble: 2 × 5
##   term         estimate std.error statistic   p.value
##   <chr>           <dbl>     <dbl>     <dbl>     <dbl>
## 1 (Intercept)     43.5      0.299     145.  0        
## 2 educ.baNo BA     7.87     0.350      22.5 2.58e-110
tidy(sweden_pop_model) |>
knitr::kable(digits = 3)
term estimate std.error statistic p.value
(Intercept) 43.491 0.299 145.376 0
educ.baNo BA 7.868 0.350 22.494 0
summary(sweden_pop_model)
## 
## Call:
## lm(formula = populist ~ educ.ba, data = sweden_data_lr)
## 
## Residuals:
##     Min      1Q  Median      3Q     Max 
## -51.359 -14.692  -1.359  11.975  56.509 
## 
## Coefficients:
##              Estimate Std. Error t value Pr(>|t|)    
## (Intercept)   43.4906     0.2992  145.38   <2e-16 ***
## educ.baNo BA   7.8681     0.3498   22.49   <2e-16 ***
## ---
## Signif. codes:  0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
## 
## Residual standard error: 19.43 on 15711 degrees of freedom
##   (因为不存在,2503个观察量被删除了)
## Multiple R-squared:  0.0312, Adjusted R-squared:  0.03114 
## F-statistic:   506 on 1 and 15711 DF,  p-value: < 2.2e-16

The intercept of Sweden is 48.32. It is the Sweden average score on the populist scale .It means have strong attitude of populist. The educ.baNo BA is 7.87.

Task 3

Now using the Italian dataset and the authoritarian values scale (as we did in the tutorial), graph the average by survey year. Interpret.

italy_data <- read.fst("italy_data.fst")
df <- read.fst("italy_data.fst")
## Creates an authoritarian values scale based on human modules items (can also do libertarian value scale)
df <- df %>%
  mutate(behave = ipbhprp,
         secure = impsafe,
         safety = ipstrgv,
         tradition = imptrad,
         rules = ipfrule) %>%
  mutate(across(c("behave", "secure", "safety", "tradition", "rules"),
                ~ na_if(.x, 7) %>% na_if(8) %>% na_if(9))) %>%
  # Apply the reverse coding
  mutate(across(c("behave", "secure", "safety", "tradition", "rules"), ~ 7 - .x ))

# Now you can calculate 'schwartzauth' after the NA recoding
df$auth <- scales::rescale(df$behave + 
                      df$secure + 
                      df$safety + 
                      df$tradition + 
                      df$rules, to=c(0,100), na.rm=TRUE)


df <- df %>% filter(!is.na(auth))
table(df$secure)
## 
##    1    2    3    4    5    6 
##   54  139  626 1856 2876 2881
table(df$auth)
## 
##   0  12  16  20  24  28  32  36  40  44  48  52  56  60  64  68  72  76  80  84 
##   7   4   4   9  13  20  27  57 113 155 163 323 367 596 647 789 823 897 992 733 
##  88  92  96 100 
## 632 465 299 297
ggplot(df, aes(x = auth)) +
  geom_histogram(bins = 30, fill = "blue", color = "black") +
  theme_minimal() +
  labs(title = "Distribution of Authoritarian Scale for italy",
       x = "Authoritarian Scale",
       y = "Count")

df$year <- NA
replacements <- c(2002, 2004, 2006, 2008, 2010, 2012, 2014, 2016, 2018, 2020)
for(i in 1:10){
  df$year[df$essround == i] <- replacements[i]
}
auth_avg <- df %>%
  group_by(year) %>%
  summarize(auth_avg = mean(auth, na.rm = TRUE))

plot_auth <- ggplot(auth_avg, aes(x = year, y = auth_avg)) +
  geom_point(aes(color = auth_avg), alpha = 1.0) + 
  geom_line(aes(group = 1), color = "blue", linetype = "dashed") +  
  labs(title = "Authoritarian Scale Average by Year (italy)",
       x = "Survey Year",
       y = "Authoritarian Scale Average") +
  theme_minimal() +
  theme(legend.position = "none") +
  scale_y_continuous(limits = c(0, 100))

print(plot_auth)

This graph show the authoritarian scale average by year of Italy. The vertical axis is represent the authoritarian scale average. It is around 75. The horizontal axis is represent the survey year from 2012 to 2020. From 2016 to 2020. The average is below 75. But it also stable.

Task 4

Now run a linear regression model, using the modelsummary package, with authoritarian values as the outcome, and generations as the predictor/potential explanatory variable, and using the Italian data again. Rename the coefficients using the coef_rename function. Interpret the coefficients, whether they are statistically significant, and the adjusted R-squared.

model_data <- df %>%
  mutate(
    # Recoding gender
    gndr = case_when(
      gndr == 1 ~ "Male",
      gndr == 2 ~ "Female",
      gndr == 9 ~ NA_character_,
      TRUE ~ as.character(gndr)
    ),

 # Recoding education
    educ.ba = case_when(
      essround < 5 & edulvla == 5 ~ "BA or more",
      essround >= 5 & edulvlb > 600 ~ "BA or more",
      TRUE ~ "No BA"
    ),
    
    # Handle NAs for education levels
    edulvla = ifelse(edulvla %in% c(77, 88, 99), NA_integer_, edulvla),
    edulvlb = ifelse(edulvlb %in% c(5555, 7777, 8888), NA_integer_, edulvlb),
    
    # Explicitly making 'No BA' the reference category
    educ.ba = factor(educ.ba, levels = c("No BA", "BA or more")),

    # Recoding age, setting 999 to NA
    age = ifelse(agea == 999, NA, agea),

    # Recoding cohort variable, setting years before 1930 and after 2000 to NA
    cohort = ifelse(yrbrn < 1930 | yrbrn > 2000, NA, yrbrn),

    # Recoding generational cohorts based on year of birth
    gen = case_when(
      yrbrn %in% 1900:1945 ~ "1",
      yrbrn %in% 1946:1964 ~ "2",
      yrbrn %in% 1965:1979 ~ "3",
      yrbrn %in% 1980:1996 ~ "4",
      TRUE ~ as.character(cohort)  # Keeping other values as character if they do not fit the ranges
    ),

    # Converting cohort to a factor with labels
    gen = factor(gen,
                 levels = c("1", "2", "3", "4"),
                 labels = c("Interwar", "Baby Boomers", "Gen X", "Millennials"))
  )
table(model_data$gen)
## 
##     Interwar Baby Boomers        Gen X  Millennials 
##         1026         2580         2214         1811
model1 <- lm(auth ~ gen, data = model_data)
modelsummary(
  list(model1),
  fmt = 1,
  estimate  = c( "{estimate} ({std.error}){stars}"),
  statistic = NULL,
  coef_rename = c("genBaby Bommers" = "Baby Boomers", "genGen X" = "Gen X", "genMillennials" = "Millennials"),
  coef_omit = "Intercept")
 (1)
genBaby Boomers -1.1 (0.6)*
Gen X -2.1 (0.6)***
Millennials -3.6 (0.6)***
Num.Obs. 7631
R2 0.006
R2 Adj. 0.006
AIC 62934.0
BIC 62968.7
Log.Lik. -31462.009
RMSE 14.94

The table show the data about baby boomers,gen x and Millennials. The gen Baby Boomers is -1.1. It means is lower than Interwar. The Gen X is -2.1. it is lower than Interwar. The genMillennials is -3.6. R square before adjust is 0.006. After adjust r square is 0.006. It is unchange.

Task 5

Now visualize, using the modelplot() function from the modelsummary package, coefficient estimates and 95% confidence intervals for the following three models:

Model 1 = populist attitudes scale as the outcome; left/right as the single predictor (omitting moderates as we did in the tutorial), and using data for Greece.

Model 2 = populist attitudes scale as the outcome; gender as the single predictor, and using data for Greece.

Model 3 = populist attitudes scale as the outcome; generations as the single predictor (using the four generational category recode we did in the tutorial), and using data for Greece. Interpret.

model1 <- lm(auth ~ gen, data = model_data)
model2 <- lm(auth ~ gndr, data = model_data)
model3 <- lm(auth ~ educ.ba, data = model_data)
models <- list(
   "Model 1" = lm(auth ~ gen, data = model_data),
   "Model 2" = lm(auth ~ gndr, data = model_data),
   "Model 3" = lm(auth ~ educ.ba, data = model_data))
modelsummary(models, fmt = 1,
  estimate  = c("{estimate} ({std.error}){stars}",
                "{estimate} ({std.error}){stars}",
                "{estimate} ({std.error}){stars}"),
  statistic = NULL)
Model 1  Model 2  Model 3
(Intercept) 75.3 (0.5)*** 74.4 (0.2)*** 73.3 (0.2)***
genBaby Boomers -1.1 (0.6)*
genGen X -2.1 (0.6)***
genMillennials -3.6 (0.6)***
gndrMale -2.6 (0.3)***
educ.baBA or more -1.1 (0.4)*
Num.Obs. 7631 8432 8432
R2 0.006 0.007 0.001
R2 Adj. 0.006 0.007 0.001
AIC 62934.0 69523.1 69579.5
BIC 62968.7 69544.3 69600.6
Log.Lik. -31462.009 -34758.566 -34786.739
RMSE 14.94 14.93 14.98

The intercept of Model 1 is 75.3. The intercept of Model 2 is 74.4. The intercept of Model 3 is 73.3.

modelplot(models, coef_omit = 'Interc')