An advertiser drops 10,000 leaflets on a city which has 2000 blocks. Assume that each leaflet has an equal chance of landing on each block. What is the probability that a particular block will receive no leaflets?
We use the Poisson distribution because:
Poisson Distribution: \(P(X = k) = \frac{\lambda^k e^{-\lambda}}{k!}\)
Expected Value; \(\mu = \lambda\)
Standard Deviation: \(\sigma = \sqrt{\lambda}\)
Poisson Distribution: \(P(X = k) = \frac{5^k e^{-5}}{0!}\)
Expected Value: \(\mu = 5\)
Standard Deviation: \(\sigma = \sqrt{5}\)
# Rate
lambda <- 5
# Probability of a block receiving exactly k leaflets
k <- 0
probability_k_leaflets <- round(dpois(k, lambda), 4)
expected_value <- lambda
standard_deviation <- round(sqrt(lambda), 4)
# Results
print(paste("Probability of a block receiving", k, "leaflets:", probability_k_leaflets))
## [1] "Probability of a block receiving 0 leaflets: 0.0067"
print(paste("Expected value:", expected_value))
## [1] "Expected value: 5"
print(paste("Standard deviation:", standard_deviation))
## [1] "Standard deviation: 2.2361"