vectors:
Create a vector containing elements 10, 22, 27, 19, 20 and assign it with a name.
# your code here
vect1<-c(10,22,27,19,20)
Use R as a calculator to compute the following values. a). 27(38-15) b).ln(14^7 ) c). sqrt(436/12)
# your code here
27*(38-15)
## [1] 621
log(14^7,base = exp(1))
## [1] 18.4734
sqrt(436/12)
## [1] 6.027714
# your code here
(b<-c(87:56))
## [1] 87 86 85 84 83 82 81 80 79 78 77 76 75 74 73 72 71 70 69 68 67 66 65 64 63
## [26] 62 61 60 59 58 57 56
b[19]
## [1] 69
b[20]
## [1] 68
b[21]
## [1] 67
compute the following statistics of b: 1) sum 2) median 3) standard deviation
# your code here
sum(b)
## [1] 2288
median(b)
## [1] 71.5
sd(b)
## [1] 9.380832
Create a vector that contains 100 elements with value of 1. (Hint: use ?rep for help). Use the option results = ’hide” in the code chuck to hide the result
# your code here
vect2<-rep(1,100)
Create a matrix with 16 elements with 4 rows both by row and column wise store it as Ex1 and Ex2
Access 3rd row 3rd column element of the matrices
Access 2nd row 1st column element of them
# your code here
(Ex1<-matrix(1:16,ncol = 4,byrow = T))
## [,1] [,2] [,3] [,4]
## [1,] 1 2 3 4
## [2,] 5 6 7 8
## [3,] 9 10 11 12
## [4,] 13 14 15 16
(Ex2<-matrix(1:16,ncol = 4,byrow = F))
## [,1] [,2] [,3] [,4]
## [1,] 1 5 9 13
## [2,] 2 6 10 14
## [3,] 3 7 11 15
## [4,] 4 8 12 16
Ex1[3,3]
## [1] 11
Ex2[3,3]
## [1] 11
Ex1[2,1]
## [1] 5
Ex2[2,1]
## [1] 2
Imagine you have data on temperature readings for different cities In Africa for 3 months. How would you create a matrix in R to store this data, with cities as rows and months as columns?
# your code here
(temp<-matrix(c(34,23,38,36,21,40,36,12,19),ncol = 3,byrow = F))
## [,1] [,2] [,3]
## [1,] 34 36 36
## [2,] 23 21 12
## [3,] 38 40 19
colnames(temp)<-c('January','February','March')
rownames(temp)<-c("Nairobi",'Nakuru','Eldoret')
temp
## January February March
## Nairobi 34 36 36
## Nakuru 23 21 12
## Eldoret 38 40 19
You need to calculate the average temperature for each city over the 3 months. How would you access and manipulate specific elements of the matrix in R to achieve this? Write the code for both row and column-wise calculations
# your code here
colMeans(temp)
## January February March
## 31.66667 32.33333 22.33333
rowMeans(temp)
## Nairobi Nakuru Eldoret
## 35.33333 18.66667 32.33333
Suppose you have information about different employees, including their name, department, age, and salary. How would you create a data frame in R to store this data? Include different data types for each variable.
# your code here
names<-c("christiano","benzema","bale","hazzard")
age<-c(39,36,34,33)
department<-c("marketing","IT","sales","HR")
salary<-c(65000,40000,45000,39000)
(employee<-data.frame(names,age,department,salary))
## names age department salary
## 1 christiano 39 marketing 65000
## 2 benzema 36 IT 40000
## 3 bale 34 sales 45000
## 4 hazzard 33 HR 39000
You want to filter the data frame to find employees in the “Marketing” department with a salary above Ksh50,000. Write the code using appropriate indexing and logical operators.
# your code here
filter(employee,department=="marketing"&salary>50000)
## Time Series:
## Start = 1
## End = 4
## Frequency = 1
## [,1] [,2] [,3] [,4]
## 1 NA NA NA NA
## 2 4 33 1 39000
## 3 NA NA NA NA
## 4 NA NA NA NA
Create a list that stores different types of data: a numeric vector, a character string, and another list.
# your code here
my_list <- list(
numeric_vector <- c(1, 2, 3),
character_string <- "Hello, world!",
another_list <- list("a", "b", "c")
)
You want to add a new element (a logical value) to the end of the list. How would you achieve this? Include different methods.
# your code here
new_list<-list("n",c(2,3),4)
new_list<-list(new_list,TRUE)
Imagine you have survey data where participants chose their favorite R packages from a set of options. How would you create a factor variable in R to store this data?
# your code here
survey_responses <- c("ggplot2", "dplyr", "tidyr", "ggplot2", "ggplot2", "dplyr")
(favorite_packages <- factor(survey_responses))
## [1] ggplot2 dplyr tidyr ggplot2 ggplot2 dplyr
## Levels: dplyr ggplot2 tidyr
You want to analyze the number of people who chose each color. How would you use the table function and factor levels to get a frequency table? Write the code and interpret the results.
# your code here
color_vector <- c("red", "blue", "green", "red", "red", "blue", "green", "yellow")
(color_freq <- table(color_vector))
## color_vector
## blue green red yellow
## 2 2 3 1
Describe the difference between is.finite(x) and !is.infinite(x).
# your answer here
#is.finite(x) checks for finiteness, while !is.infinite(x) checks for non-infiniteness