Find a 95% two-sided confidence interval for the mean survival time of cancer patients in this data set.
\(\bar{x}\) = 305.2324561
\(\sigma\) = 210.6455431
n = 228
\(1 - \alpha = .95\), so \(\alpha = .05\)
\(\hat{L}\) = 305.2324561 - \(z_\frac{\\.05}{2}\frac{210.6455431}{\sqrt{228}} = 277.7437328\)
\(\hat{U}\) = 305.2324561 + \(z_\frac{\\.05}{2}\frac{210.6455431}{\sqrt{228}} = 332.7211795\)
Conclusion: Based on the sample data, the probability that the interval (277.7437, 332.7212) contains the true mean, \(\mu\), of survival time of cancer patients, is 0.95.