C23 Doing the computations by hand, find the determinant of the matrix below. I will use the diagonal method to find the determinant
\[ A= \begin{bmatrix}
1 & 3 & 2 \\
4 & 1 & 3 \\
1 & 0 & 1 \\
\end{bmatrix} \] \[ \begin{bmatrix}
1 & 3 & 2 & 1 & 3\\
4 & 1 & 3 & 4 & 1\\
1 & 0 & 1 & 1 & 0 \\
\end{bmatrix} \] multiply the diagonal from left to right and
take the sum of the product then multiply the diagonal from right to
left and take the sum of the product subtract the sum of the product of
right to left diagonal from the product of left to right to find the
determinant
(1+9+0) - (2+0+12) = 10 - 14 = -4
det(A) = -4