Find all solutions to the linear system: x + y − z = −1 x − y − z = −1 z = 2
Since the third equation directly gives z=2, we can substitute this value into the first two equations, simplifying the system.
# Coefficients matrix
A <- matrix(c(1, 1, -1,
1, -1, -1,
0, 0, 1), nrow = 3, byrow = TRUE)
# Constants vector
b <- c(-1, -1, 2)
# Solve the system
solution <- solve(A, b)
# Print the solution
print(solution)
## [1] 1 0 2