# List of packages
packages <- c("tidyverse", "fst", "modelsummary", "viridis") # add any you need here

# Install packages if they aren't installed already
new_packages <- packages[!(packages %in% installed.packages()[,"Package"])]
if(length(new_packages)) install.packages(new_packages)

# Load the packages
lapply(packages, library, character.only = TRUE)
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Task 1

Provide code and answer.

Prompt: in the tutorial, we calculated the average trust in others for France and visualized it. Using instead the variable ‘Trust in Parliament’ (trstplt) and the country of Spain (country file provided on course website), visualize the average trust by survey year. You can truncate the y-axis if you wish. Provide appropriate titles and labels given the changes. What are your main takeaways based on the visual (e.g., signs of increase, decrease, or stall)?

The data from 2002 to 2020 reveal a general decreasing trend in mean trust levels, indicating a gradual decline in trust over these years. Notably, there was a slight increase in trust from 2002 to 2004. However, this was followed by a sharp decline, particularly between 2008 and 2012. The years 2012 and 2020 are marked by significantly low mean trust levels, underscoring particularly low levels of trust in Parliament during these periods.

spain_data <- read.fst("spain_data.fst")
spain_data <- spain_data %>%
  mutate(
    trstplt = ifelse(trstplt %in% c(77, 88, 99), NA, trstplt) # set values 77, 88, and 99 to NA
  )
table(spain_data$trstplt)
## 
##    0    1    2    3    4    5    6    7    8    9   10 
## 5165 1830 2329 2441 2085 2890 1154  639  355   80   71
spain_data$year <- NA
replacements <- c(2002, 2004, 2006, 2008, 2010, 2012, 2014, 2016, 2018, 2020)
for(i in 1:10){
  spain_data$year[spain_data$essround == i] <- replacements[i]
}
table(spain_data$year)
## 
## 2002 2004 2006 2008 2010 2012 2014 2016 2018 2020 
## 1729 1663 1876 2576 1885 1889 1925 1958 1668 2283
trust_by_year <- spain_data %>%
  group_by(year) %>%
  summarize(mean_trust = mean(trstplt, na.rm = TRUE))
trust_by_year
## # A tibble: 10 × 2
##     year mean_trust
##    <dbl>      <dbl>
##  1  2002       3.41
##  2  2004       3.66
##  3  2006       3.49
##  4  2008       3.32
##  5  2010       2.72
##  6  2012       1.91
##  7  2014       2.23
##  8  2016       2.40
##  9  2018       2.55
## 10  2020       1.94
ggplot(trust_by_year, aes(x = year, y = mean_trust)) +
  geom_line(color = "blue", size = 1, linetype = "longdash") +
    geom_point(color = "red", size = 2) +  
  labs(title = "Average Trust in Parliament in Spain (2002-2020)", 
       x = "Survey Year", 
       y = "Average Trust in Parliament (0-10 scale)") +
  ylim(0, 10) +
    scale_x_continuous(breaks = seq(min(trust_by_year$year), max(trust_by_year$year), by = 2)) +
  theme_minimal() +
  theme(legend.position = "none")
## Warning: Using `size` aesthetic for lines was deprecated in ggplot2 3.4.0.
## ℹ Please use `linewidth` instead.
## This warning is displayed once every 8 hours.
## Call `lifecycle::last_lifecycle_warnings()` to see where this warning was
## generated.

## X-Axis label has been adjusted to show two-year increments to display yearly trends clearly.

Task 2

Provide answer only.

Prompt and question: Based on the figure we produced above called task2_plot, tell us: what are your main takeaways regarding France relative to Italy and Norway? Make sure to be concrete and highlight at least two important comparative trends visualized in the graph.

Task 3

Provide code and answer.

Question: What is the marginal percentage of Italian men who feel close to a particular political party?

The marginal percentage of italian men who feel close to a prarticular political party is 20.501%

italy_data <- read.fst("italy_data.fst")
Italy_data <- italy_data %>%
  mutate(
    gndr = case_when(
      gndr == 1 ~ "Male",
      gndr == 2 ~ "Female",
      TRUE ~ NA_character_  
    ),
    clsprty  = case_when(
      clsprty  %in% 1 ~ "Yes",       
      clsprty  %in% 0 ~ "No",     
      TRUE ~ NA_character_  
    )    
  )
clsprty_percentages <- italy_data %>%  
  filter(!is.na(clsprty), !is.na(gndr)) %>%  
  group_by(gndr, clsprty) %>%  
  summarise(count = n(), .groups = 'drop') %>%  
  mutate(percentage = count / sum(count) * 100)  

clsprty_percentages  
## # A tibble: 12 × 4
##     gndr clsprty count percentage
##    <dbl>   <dbl> <int>      <dbl>
##  1     1       1  1936    19.0   
##  2     1       2  2593    25.5   
##  3     1       7   142     1.40  
##  4     1       8   165     1.62  
##  5     2       1  1686    16.6   
##  6     2       2  3228    31.7   
##  7     2       7   180     1.77  
##  8     2       8   233     2.29  
##  9     2       9     2     0.0197
## 10     9       1     4     0.0393
## 11     9       2     7     0.0688
## 12     9       8     2     0.0197

Task 4

Provide code and output only.

Prompt: In the tutorial, we calculated then visualized the percentage distribution for left vs. right by gender for France. Your task is to replicate the second version of the visualization but for the country of Sweden instead.

sweden_data <- read.fst("sweden_data.fst")
sweden_data <- sweden_data %>%
  mutate(
    gndr = case_when(
      gndr == 1 ~ "Male",
      gndr == 2 ~ "Female",
      TRUE ~ NA_character_  # Set anything that is not 1 or 2 to NA
    ),
    lrscale = case_when(
      lrscale %in% 0:3 ~ "Left",       # Left-wing (0 to 3)
      lrscale %in% 7:10 ~ "Right",     # Right-wing (7 to 10)
      TRUE ~ NA_character_  # Moderate (4, 5, 6) and special codes (77, 88, 99) set to NA 
    )    
  ) 
lrscale_percentages <- sweden_data %>%  # Begin with the dataset 'sweden_data'
  filter(!is.na(lrscale), !is.na(gndr)) %>%  # Filter out rows where 'lrscale' or 'gender' is NA (missing data)
  group_by(gndr, lrscale) %>%  # Group the data by 'gender' and 'lrscale' categories
  summarise(count = n(), .groups = 'drop') %>%  # Summarise each group to get counts, and then drop groupings
  mutate(percentage = count / sum(count) * 100)  # Calculate percentage for each group by dividing count by total count and multiplying by 100

lrscale_percentages  # The resulting dataframe
## # A tibble: 4 × 4
##   gndr   lrscale count percentage
##   <chr>  <chr>   <int>      <dbl>
## 1 Female Left     2296       23.0
## 2 Female Right    2530       25.3
## 3 Male   Left     2062       20.6
## 4 Male   Right    3107       31.1
lrscale_plot <- ggplot(lrscale_percentages, aes(x = lrscale, y = percentage, fill = lrscale)) +
  geom_bar(stat = "identity", position = position_dodge()) +  # Dodged bar chart
  facet_wrap(~ gndr, scales = "fixed") +  # Fixed scales for y-axis across facets
  scale_fill_brewer(palette = "Set1") +  # Distinct colors for Left and Right
  labs(
    title = "Political Orientation (Left vs. Right) by Gender in Sweden",
    x = "Political Orientation",
    y = "Percentage of Respondents",
    fill = "Orientation"
  ) +
  theme_minimal() +  # Minimal theme for clarity
  theme(legend.position = "bottom")  # Legend at the bottom

# Display the ggplot object
lrscale_plot

Task 5

Provide code and answer: In Hungary, what is the conditional probability of NOT feeling close to any particular party given that the person lives in a rural area?

The conditional probability of those who live in rural areas and do not feel close to any particular party is 55.38394%

hungary_data <- read.fst("hungary_data.fst")
hungary_data <- hungary_data %>%
  mutate(
    geo = recode(as.character(domicil), 
                 '1' = "Urban", 
                 '2' = "Urban",
                 '3' = "Rural", 
                 '4' = "Rural", 
                 '5' = "Rural",
                 '7' = NA_character_,
                 '8' = NA_character_,
                 '9' = NA_character_)
  ) %>%
  filter(!is.na(clsprty), !is.na(geo))  
hungary_data <- hungary_data %>%
  mutate(
    clsprty  = case_when(
      clsprty  %in% 1 ~ "Yes",       
      clsprty  %in% 2 ~ "No",    
      TRUE ~ NA_character_  
    ) 
  ) %>%
      
  filter(!is.na(clsprty))
cond <- hungary_data %>%
  count(clsprty, geo) %>%
  group_by(geo) %>%
  mutate(prob = n / sum(n)*100)

cond
## # A tibble: 4 × 4
## # Groups:   geo [2]
##   clsprty geo       n  prob
##   <chr>   <chr> <int> <dbl>
## 1 No      Rural  6275  55.4
## 2 No      Urban  2395  51.2
## 3 Yes     Rural  5055  44.6
## 4 Yes     Urban  2283  48.8