Utilizing Supervised Learning in Learning Analytics
Case Study 4
Author
Amandeep Singh
Business Scenario: Predicting Student Performance
In this case study, you are an analyst at an online education platform. The management is interested in predicting student performance based on various factors to provide personalized support and improve the learning experience. Your task is to develop a supervised learning model to predict students’ final grades using simulated data.
Objective:
Your goal is to build a predictive model using supervised learning techniques in R. You will utilize simulated student data with features such as study hours, quiz scores, forum participation, and previous grades to predict the final grades.
Data Generation:
# Set a fixed random seed for reproducibilityset.seed(10923)# Number of students#TODO: set num_students to 500# Enter code below:num_students <-500# Simulate study hours (ranging from 1 to 20 hours)study_hours <-sample(1:20, num_students, replace =TRUE)# Simulate quiz scores (ranging from 0 to 100)quiz_scores <-sample(0:100, num_students, replace =TRUE)# Simulate forum participation (ranging from 0 to 50 posts)forum_posts <-sample(0:50, num_students, replace =TRUE)# Simulate previous grades (ranging from 0 to 100)previous_grades <-sample(0:100, num_students, replace =TRUE)# Simulate final grades (ranging from 0 to 100)final_grades <-0.3* study_hours +0.4* quiz_scores +0.2* forum_posts +0.1* previous_grades +rnorm(num_students, mean =0, sd =5) +25# Create a data framestudent_data <-data.frame(StudyHours = study_hours, QuizScores = quiz_scores, ForumPosts = forum_posts, PreviousGrades = previous_grades, FinalGrades = final_grades)# View the first few rows of the generated datahead(student_data)
# Summary statistics of the datasummary(student_data)
StudyHours QuizScores ForumPosts PreviousGrades
Min. : 1.00 Min. : 0.00 Min. : 0.00 Min. : 0.00
1st Qu.: 6.00 1st Qu.: 24.00 1st Qu.:12.00 1st Qu.: 23.00
Median :11.00 Median : 48.00 Median :24.00 Median : 51.00
Mean :10.67 Mean : 48.54 Mean :24.26 Mean : 50.05
3rd Qu.:16.00 3rd Qu.: 73.00 3rd Qu.:37.00 3rd Qu.: 75.00
Max. :20.00 Max. :100.00 Max. :50.00 Max. :100.00
FinalGrades
Min. :24.19
1st Qu.:47.15
Median :57.18
Mean :57.35
3rd Qu.:67.01
Max. :95.36
# Load required librarieslibrary(ggplot2)
Warning: package 'ggplot2' was built under R version 4.3.1
library(corrplot)
Warning: package 'corrplot' was built under R version 4.3.1
corrplot 0.92 loaded
# Visualize the distribution of each variable# Histogram for Study Hoursggplot(student_data, aes(x = StudyHours)) +geom_histogram(fill ="lightblue", color ="black") +labs(title ="Distribution of Study Hours")
`stat_bin()` using `bins = 30`. Pick better value with `binwidth`.
# Histogram for Quiz Scoresggplot(student_data, aes(x = QuizScores)) +geom_histogram(fill ="lightgreen", color ="black") +labs(title ="Distribution of Quiz Scores")
`stat_bin()` using `bins = 30`. Pick better value with `binwidth`.
# Histogram for Forum Postsggplot(student_data, aes(x = ForumPosts)) +geom_histogram(fill ="lightyellow", color ="black") +labs(title ="Distribution of Forum Posts")
`stat_bin()` using `bins = 30`. Pick better value with `binwidth`.
# Histogram for Previous Gradesggplot(student_data, aes(x = PreviousGrades)) +geom_histogram(fill ="pink", color ="black") +labs(title ="Distribution of Previous Grades")
`stat_bin()` using `bins = 30`. Pick better value with `binwidth`.
# Scatterplot matrix to visualize the relationships between variablesscatterplotMatrix <-ggplot(student_data, aes(x = StudyHours, y = QuizScores)) +geom_point(aes(color = FinalGrades)) +labs(title ="Scatterplot Matrix")# Correlation matrix to check the correlation between variablescorrelation_matrix <-cor(student_data[, -5])corrplot(correlation_matrix, method ="color")
Modeling
Use 80% of the data for training and 20% for testing to predict final grades. Compute the Mean Squared Error and model accuracy based on prediction interval.
# Todo:# Splitting the data into training and testing sets (80% training, 20% testing)set.seed(10923) # Set seed for reproducibilitysample_index <-sample(1:nrow(student_data), 0.8*nrow(student_data))train_data <- student_data[sample_index, ]test_data <- student_data[-sample_index, ]# Building a Linear Regression model using the train data and assign it to an object # called model.# Todo: Target variable is FinalGrades and the Features are StudyHours, QuizScores, # ForumPosts, and PreviousGrades# Enter code below:model <-lm(FinalGrades ~ StudyHours + QuizScores + ForumPosts + PreviousGrades, data = train_data)# Making predictions on the test set. use the model object to make prediction.# Enter code below:predictions <-predict(model, newdata = test_data)# Evaluation metrics# Compute the mean squared error and R-squared# Enter code belowmean_squared_error <-mean((test_data$FinalGrades - predictions)^2)rsquared <-summary(model)$r.squared# Print evaluation metrics#Enter code belowprint(paste("Mean Squared Error:", mean_squared_error))
[1] "Mean Squared Error: 22.3465631070855"
print(paste("R-squared:", rsquared))
[1] "R-squared: 0.864833778721095"
Interpretation
Mean Squared Error (MSE) indicates the average of the squares of the differences between the actual and the predicted value of the “FinalGrades”. MSE of 22.35 shows that the model has smaller prediction errors on average, which means it is a reasonably accurate predictive performance.
R-Squared is a statistical measure that represents the proportion of the variance in the dependent variable that is predictable from the independent variables. Here “FinalGrades” is the dependent variable and “StudyHours”, “QuizScores”, “ForumPosts” and “PreviousGrades” are the independent variables. R-squared value of 0.8648 indicates that approximately86.48% of the variance in the “FinalGrades” can be explained by the independent variables included in the model. It also indicates that model is a good fit.
Model Accuracy based on Prediction Interval
# Get the predictions and prediction intervalspred_int <-predict(model, newdata = test_data, interval ="prediction")# Extract lower and upper bounds of the prediction intervallower_bound <- pred_int[, "lwr"]upper_bound <- pred_int[, "upr"]# Actual values from the test dataactual_values <- test_data$FinalGrades# Check if the actual values fall within the prediction intervalcorrect_predictions <- actual_values >= lower_bound & actual_values <= upper_bound# Compute accuracyaccuracy <-sum(correct_predictions) /length(correct_predictions)# Print accuracycat("Model Accuracy using Prediction Interval:", accuracy, "\n")
Model Accuracy using Prediction Interval: 0.96
The accuracy is calculated as the proportion of correct predictions.