library(readxl)
Chi_square_for_goodness_of_fit <- read_excel("D:/MARV BS MATH/4th year, 2nd sem/Nonparametric Statistics/Final Exam/Chi-square for goodness-of-fit.xlsx")
Chi_square_for_goodness_of_fit
# A tibble: 6 × 2
Day Frequency
<chr> <dbl>
1 Monday 20
2 Tuesday 14
3 Wednesday 18
4 Thursday 17
5 Friday 22
6 Saturday 29
head(Chi_square_for_goodness_of_fit)
# A tibble: 6 × 2
Day Frequency
<chr> <dbl>
1 Monday 20
2 Tuesday 14
3 Wednesday 18
4 Thursday 17
5 Friday 22
6 Saturday 29
summary(Chi_square_for_goodness_of_fit)
Day Frequency
Length:6 Min. :14.00
Class :character 1st Qu.:17.25
Mode :character Median :19.00
Mean :20.00
3rd Qu.:21.50
Max. :29.00
res <- chisq.test(Chi_square_for_goodness_of_fit$Frequency, p = c(1/6, 1/6, 1/6, 1/6, 1/6, 1/6))
res
Chi-squared test for given probabilities
data: Chi_square_for_goodness_of_fit$Frequency
X-squared = 6.7, df = 5, p-value = 0.2439
Since the p value is 0.2439 which is greater than the significant level 0.05, we don’t have enough evidence to reject the null hypothesis. Thus, there is significant difference between a person will take a book out of the library each of the six days of the week when the library is open and number of books signed out of the library during that week.
res$expected
[1] 20 20 20 20 20 20