Null Hypothesis: The true mean difference between S. aureus and S. marcescens with the given concentration is equal to zero.

Alternative Hypothesis: The true mean difference between S. aureus and S. marcescens with the given concentration is not equal to zero.

shapiro.test(PLANT$SAMean128) 

    Shapiro-Wilk normality test

data:  PLANT$SAMean128
W = 0.93772, p-value = 0.6182

Not normally distributed.

shapiro.test(PLANT$SAENMean128) 

    Shapiro-Wilk normality test

data:  PLANT$SAENMean128
W = 0.92946, p-value = 0.5463

Normally distributed.

t.test(PLANT$SAMean128,PLANT$SAENMean128,paired=FALSE)

    Welch Two Sample t-test

data:  PLANT$SAMean128 and PLANT$SAENMean128
t = 1.821, df = 11.817, p-value = 0.09401
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
 -0.01014526  0.11233574
sample estimates:
 mean of x  mean of y 
0.11890476 0.06780952

Since the p-value is 0.7435 is greater than the significance level 0.05, we don’t have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 128mg/ml is equal to zero.

shapiro.test(PLANT$SAMean64) 

    Shapiro-Wilk normality test

data:  PLANT$SAMean64
W = 0.96956, p-value = 0.8953

Normally distributed.

shapiro.test(PLANT$SAENMean64) 

    Shapiro-Wilk normality test

data:  PLANT$SAENMean64
W = 0.93959, p-value = 0.635

Normally distributed.

t.test(PLANT$SAMean64,PLANT$SAENMean64,paired=TRUE)

    Paired t-test

data:  PLANT$SAMean64 and PLANT$SAENMean64
t = 9.1727, df = 6, p-value = 9.456e-05
alternative hypothesis: true mean difference is not equal to 0
95 percent confidence interval:
 0.2266059 0.3914893
sample estimates:
mean difference 
      0.3090476

Since the p-value is 2.201e-05 is less than the significance level 0.05, we have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 64mg/ml is not equal to zero.

shapiro.test(PLANT$SAMean32) 

    Shapiro-Wilk normality test

data:  PLANT$SAMean32
W = 0.72242, p-value = 0.00648

Not normally distributed.

shapiro.test(PLANT$SAENMean32) 

    Shapiro-Wilk normality test

data:  PLANT$SAENMean32
W = 0.94691, p-value = 0.7015

Normally distributed.

t.test(PLANT$SAMean32,PLANT$SAENMean32,paired=FALSE)

    Welch Two Sample t-test

data:  PLANT$SAMean32 and PLANT$SAENMean32
t = 6.1398, df = 6.7745, p-value = 0.0005367
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
 0.2529497 0.5733360
sample estimates:
 mean of x  mean of y 
0.47804762 0.06490476

Since the p-value is 0.003255 is less than the significance level 0.05, we have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 32mg/ml is not equal to zero.

shapiro.test(PLANT$SAMean16) 

    Shapiro-Wilk normality test

data:  PLANT$SAMean16
W = 0.76071, p-value = 0.01639

Normally distributed.

shapiro.test(PLANT$SAENMean16) 

    Shapiro-Wilk normality test

data:  PLANT$SAENMean16
W = 0.95175, p-value = 0.7456

Normally distributed.

t.test(PLANT$SAMean16,PLANT$SAENMean16,paired=FALSE)

    Welch Two Sample t-test

data:  PLANT$SAMean16 and PLANT$SAENMean16
t = 4.1417, df = 11.62, p-value = 0.001462
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
 0.04803265 0.15549116
sample estimates:
 mean of x  mean of y 
0.16366667 0.06190476

Since the p-value is 1.84e-07 is less than the significance level 0.05, we have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 16mg/ml is not equal to zero.

shapiro.test(PLANT$SAMean8) 

    Shapiro-Wilk normality test

data:  PLANT$SAMean8
W = 0.66912, p-value = 0.00169

Normally distributed.

shapiro.test(PLANT$SAENMean8) 

    Shapiro-Wilk normality test

data:  PLANT$SAENMean8
W = 0.95212, p-value = 0.749

Normally distributed.

t.test(PLANT$SAMean8,PLANT$SAENMean8,paired=FALSE)

    Welch Two Sample t-test

data:  PLANT$SAMean8 and PLANT$SAENMean8
t = 4.6256, df = 8.0273, p-value = 0.001683
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
 0.08632687 0.25776837
sample estimates:
 mean of x  mean of y 
0.22957143 0.05752381

Since the p-value is 0.03274 is less than the significance level 0.05, we have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 8mg/ml is not equal to zero.

shapiro.test(PLANT$SAMean4) 

    Shapiro-Wilk normality test

data:  PLANT$SAMean4
W = 0.8447, p-value = 0.1099

Normally distributed.

shapiro.test(PLANT$SAENMean4)

    Shapiro-Wilk normality test

data:  PLANT$SAENMean4
W = 0.96343, p-value = 0.8476

Normally distributed.

t.test(PLANT$SAMean4,PLANT$SAENMean4,paired=TRUE)

    Paired t-test

data:  PLANT$SAMean4 and PLANT$SAENMean4
t = 3.6374, df = 6, p-value = 0.01087
alternative hypothesis: true mean difference is not equal to 0
95 percent confidence interval:
 0.02208441 0.11286797
sample estimates:
mean difference 
     0.06747619

Since the p-value is 0.7582 is greater than the significance level 0.05, we don’t have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 4mg/ml is equal to zero.

shapiro.test(PLANT$SAMean2) 

    Shapiro-Wilk normality test

data:  PLANT$SAMean2
W = 0.83266, p-value = 0.0848

Normally distributed.

shapiro.test(PLANT$SAENMean2)

    Shapiro-Wilk normality test

data:  PLANT$SAENMean2
W = 0.97374, p-value = 0.924

Normally distributed.

t.test(PLANT$SAMean2,PLANT$SAENMean2,paired=TRUE)

    Paired t-test

data:  PLANT$SAMean2 and PLANT$SAENMean2
t = 5.4779, df = 6, p-value = 0.001546
alternative hypothesis: true mean difference is not equal to 0
95 percent confidence interval:
 0.04776933 0.12489734
sample estimates:
mean difference 
     0.08633333

Since the p-value is 0.8814 is less than the significance level 0.05, we don’t have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 2mg/ml is equal to zero.

shapiro.test(PLANT$SAMean1)

    Shapiro-Wilk normality test

data:  PLANT$SAMean1
W = 0.58592, p-value = 0.0001856

Not normally distributed.

shapiro.test(PLANT$SAENMean1)

    Shapiro-Wilk normality test

data:  PLANT$SAENMean1
W = 0.9329, p-value = 0.5758

Normally distributed.

t.test(PLANT$SAMean1,PLANT$SENMean1,paired=FALSE)

    Welch Two Sample t-test

data:  PLANT$SAMean1 and PLANT$SENMean1
t = -1.7922, df = 7.3679, p-value = 0.1141
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
 -0.15802595  0.02097833
sample estimates:
 mean of x  mean of y 
0.06980952 0.13833333

Since the p-value is 0.0007247 is less than the significance level 0.05, we have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 1mg/ml is not equal to zero.

shapiro.test(PLANT$SENMean128)

    Shapiro-Wilk normality test

data:  PLANT$SENMean128
W = 0.9491, p-value = 0.7215

Normally distributed.

shapiro.test(PLANT$SMMean128)

    Shapiro-Wilk normality test

data:  PLANT$SMMean128
W = 0.87322, p-value = 0.198

Normally distributed.

t.test(PLANT$SENMean128,PLANT$SMMean128,paired=TRUE)

    Paired t-test

data:  PLANT$SENMean128 and PLANT$SMMean128
t = -3.2338, df = 6, p-value = 0.01782
alternative hypothesis: true mean difference is not equal to 0
95 percent confidence interval:
 -0.68032820 -0.09424323
sample estimates:
mean difference 
     -0.3872857

Since the p-value is 0.01021 is less than the significance level 0.05, we have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 128mg/ml is not equal to zero.

shapiro.test(PLANT$SENMean64)

    Shapiro-Wilk normality test

data:  PLANT$SENMean64
W = 0.96786, p-value = 0.8827

Normally distributed.

shapiro.test(PLANT$SMMean64)

    Shapiro-Wilk normality test

data:  PLANT$SMMean64
W = 0.92346, p-value = 0.4968

Normally distributed.

t.test(PLANT$SENMean64,PLANT$SMMean64,paired=TRUE)

    Paired t-test

data:  PLANT$SENMean64 and PLANT$SMMean64
t = -2.3573, df = 6, p-value = 0.05649
alternative hypothesis: true mean difference is not equal to 0
95 percent confidence interval:
 -0.288136359  0.005374454
sample estimates:
mean difference 
      -0.141381

Since the p-value is 0.009795 is less than the significance level 0.05, we have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 64mg/ml is not equal to zero.

shapiro.test(PLANT$SENMean32)

    Shapiro-Wilk normality test

data:  PLANT$SENMean32
W = 0.97, p-value = 0.8985

Not normally distributed.

shapiro.test(PLANT$SMMean32)

    Shapiro-Wilk normality test

data:  PLANT$SMMean32
W = 0.82329, p-value = 0.06906

Not normally distributed.

t.test(PLANT$SENMean32,PLANT$SMMean32,paired=FALSE)

    Welch Two Sample t-test

data:  PLANT$SENMean32 and PLANT$SMMean32
t = -4.4792, df = 10.226, p-value = 0.001117
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
 -0.3498402 -0.1178740
sample estimates:
 mean of x  mean of y 
0.09595238 0.32980952

Since the p-value is 0.0002184 is less than the significance level 0.05, we have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 32mg/ml is not equal to zero.

shapiro.test(PLANT$SENMean16)

    Shapiro-Wilk normality test

data:  PLANT$SENMean16
W = 0.96286, p-value = 0.8429

Normally distributed.

shapiro.test(PLANT$SMMean16)

    Shapiro-Wilk normality test

data:  PLANT$SMMean16
W = 0.85092, p-value = 0.1253

Not normally distributed.

t.test(PLANT$SENMean16,PLANT$SMMean16,paired=FALSE)

    Welch Two Sample t-test

data:  PLANT$SENMean16 and PLANT$SMMean16
t = -2.5357, df = 11.771, p-value = 0.02647
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
 -0.24992011 -0.01865131
sample estimates:
mean of x mean of y 
0.1184286 0.2527143

Since the p-value is 0.004263 is less than the significance level 0.05, we have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 16mg/ml is not equal to zero.

shapiro.test(PLANT$SENMean8)

    Shapiro-Wilk normality test

data:  PLANT$SENMean8
W = 0.96305, p-value = 0.8444

Normally distributed.

shapiro.test(PLANT$SMMean8)

    Shapiro-Wilk normality test

data:  PLANT$SMMean8
W = 0.81973, p-value = 0.06384

Normally distributed.

t.test(PLANT$SENMean8,PLANT$SMMean8,paired=FALSE)

    Welch Two Sample t-test

data:  PLANT$SENMean8 and PLANT$SMMean8
t = -2.3825, df = 11.138, p-value = 0.03608
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
 -0.27801718 -0.01122092
sample estimates:
mean of x mean of y 
 0.126000  0.270619

Since the p-value is 0.01591 is less than the significance level 0.05, we have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 8mg/ml is not equal to zero.

shapiro.test(PLANT$SENMean4)

    Shapiro-Wilk normality test

data:  PLANT$SENMean4
W = 0.95922, p-value = 0.812

Not normally distributed.

shapiro.test(PLANT$SMMean4)

    Shapiro-Wilk normality test

data:  PLANT$SMMean4
W = 0.86619, p-value = 0.1718

Normally distributed.

t.test(PLANT$SMPCMean4,PLANT$SMMean4,paired=FALSE)

    Welch Two Sample t-test

data:  PLANT$SMPCMean4 and PLANT$SMMean4
t = -3.1202, df = 6.0001, p-value = 0.02058
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
 -0.37952569 -0.04590288
sample estimates:
 mean of x  mean of y 
0.03795238 0.25066667

Since the p-value is 0.2932 is greater than the significance level 0.05, we don’t have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 4mg/ml is equal to zero.

shapiro.test(PLANT$SENMean2)

    Shapiro-Wilk normality test

data:  PLANT$SENMean2
W = 0.95889, p-value = 0.8091

Normally distributed.

shapiro.test(PLANT$SMMean2)

    Shapiro-Wilk normality test

data:  PLANT$SMMean2
W = 0.91166, p-value = 0.4075

Normally distributed.

t.test(PLANT$SENMean2,PLANT$SMMean2,paired=TRUE)

    Paired t-test

data:  PLANT$SENMean2 and PLANT$SMMean2
t = -7.2565, df = 6, p-value = 0.0003481
alternative hypothesis: true mean difference is not equal to 0
95 percent confidence interval:
 -0.15154952 -0.07511715
sample estimates:
mean difference 
     -0.1133333

Since the p-value is 0.2482 is greater than the significance level 0.05, we don’t have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 2mg/ml is equal to zero.

shapiro.test(PLANT$SENMean1)

    Shapiro-Wilk normality test

data:  PLANT$SENMean1
W = 0.95077, p-value = 0.7367

Normally distributed.

shapiro.test(PLANT$SMMean1)

    Shapiro-Wilk normality test

data:  PLANT$SMMean1
W = 0.96234, p-value = 0.8385

Normally distributed.

t.test(PLANT$SENMean1,PLANT$SMMean1,paired=TRUE)

    Paired t-test

data:  PLANT$SENMean1 and PLANT$SMMean1
t = -1.1256, df = 6, p-value = 0.3033
alternative hypothesis: true mean difference is not equal to 0
95 percent confidence interval:
 -0.04745794  0.01755318
sample estimates:
mean difference 
    -0.01495238

Since the p-value is 0.02078 is greater than the significance level 0.05, we have enough evidence to reject the null hypothesis. Thus, the true mean difference between S. aureus and S. marcescens with the concentration of 4mg/ml is not equal to zero.