Data Import

  1. Download chickens.csv to your working directory. Make sure to set your working directory appropriately! This dataset was created by modifying the R built-in dataset chickwts.

  2. Import the chickens.csv data into R. Store it in a data.frame named ch_df and print out the entire ch_df to the screen.

library(tidyverse)
## ── Attaching packages ─────────────────────────────────────── tidyverse 1.3.2 ──
## ✔ ggplot2 3.4.0     ✔ purrr   1.0.1
## ✔ tibble  3.1.8     ✔ dplyr   1.1.0
## ✔ tidyr   1.3.0     ✔ stringr 1.5.0
## ✔ readr   2.1.3     ✔ forcats 1.0.0
## ── Conflicts ────────────────────────────────────────── tidyverse_conflicts() ──
## ✖ dplyr::filter() masks stats::filter()
## ✖ dplyr::lag()    masks stats::lag()
ch_df <- read_csv("chickens.csv")
## Rows: 71 Columns: 2
## ── Column specification ────────────────────────────────────────────────────────
## Delimiter: ","
## chr (2): weight, feed
## 
## ℹ Use `spec()` to retrieve the full column specification for this data.
## ℹ Specify the column types or set `show_col_types = FALSE` to quiet this message.
ch_df
## # A tibble: 71 × 2
##    weight feed     
##    <chr>  <chr>    
##  1 206    meatmeal 
##  2 140    horsebean
##  3 <NA>   <NA>     
##  4 318    sunflower
##  5 332    casein   
##  6 na     horsebean
##  7 216    na       
##  8 143    horsebean
##  9 271    soybean  
## 10 315    meatmeal 
## # … with 61 more rows

Clean Missing Values

There are some missing values in this dataset. Unfortunately they are represented in a number of different ways.

  1. Clean up this dataset by doing the following:
num_na <- sum(is.na(ch_df))
# There are 12 NA elements in the original ch_df
ch_df <- ch_df %>%
  mutate_all(~ifelse(. %in% c("-", "?", "na"), NA, .))

Now that the dataset is clean, let’s see what percentage of our data is missing.

  1. Calculate the percentage of missing data from the weight column, the feed column, and the entire dataset. Print out each result in the following format: “Percentage of missing data in [fill in the column or dataset name]: [fill in percentage]%.”
weight_na_pct <- round(sum(is.na(ch_df$weight)) / nrow(ch_df) * 100, 2)
feed_na_pct <- round(sum(is.na(ch_df$feed)) / nrow(ch_df) * 100, 2)
total_na_pct <- round(num_na / (nrow(ch_df) * ncol(ch_df)) * 100, 2)
cat("Percentage of missing data in weight column:", weight_na_pct, "%\n")
## Percentage of missing data in weight column: 16.9 %
cat("Percentage of missing data in feed column:", feed_na_pct, "%\n")
## Percentage of missing data in feed column: 14.08 %
cat("Percentage of missing data in entire dataset:", total_na_pct, "%\n")
## Percentage of missing data in entire dataset: 8.45 %

EXTRA CREDIT (Optional): Figure out how to create these print statements so that the name and percentage number are not hard-coded into the statement. In other words, so that the name and percentage number are read in dynamically (for example, from a variable, from a function call, etc.) instead of just written in the statement. Please ask me for clarification if necessary.

# fill in your code here

Data Investigation

  1. Group the data by feed and find the mean and median weight for each group. Your result should be a new data frame with the group means in a column named weight_mean and the group medians in a column named weight_median. Save this new data frame; you can name the data frame as you wish. (Remember that variable names should be somewhat descriptive of what they contain.)
ch_df <- ch_df %>%
  mutate(weight = as.numeric(weight))
## Warning: There was 1 warning in `mutate()`.
## ℹ In argument: `weight = as.numeric(weight)`.
## Caused by warning:
## ! NAs introduced by coercion
# This was done to solve errors in my code due to the weight column being read as character values
feed_stats <- ch_df %>%
  group_by(feed) %>%
  summarize(weight_mean = mean(weight, na.rm = TRUE), 
            weight_median = median(weight, na.rm = TRUE))
feed_stats
## # A tibble: 9 × 3
##   feed      weight_mean weight_median
##   <chr>           <dbl>         <dbl>
## 1 casein           314.          325 
## 2 horsebean        161.          160 
## 3 linseed          232.          236.
## 4 meatmeal         304.          315 
## 5 not sure         329           329 
## 6 soybean          242.          249 
## 7 sunflower        353.          340 
## 8 unknown          263           263 
## 9 <NA>             241.          217
  1. Find the feed that has the maximum median chicken weight.
max_median_feed <- feed_stats %>%
  filter(weight_median == max(weight_median)) %>%
  pull(feed)

Sunflower has the maximum median chicken weight

  1. Create a quick histogram of the weight from the original data frame using the Base R Plotting package.
hist(ch_df$weight)

  1. Create a box plot with feed type as the X axis.
boxplot(weight ~ feed, data = ch_df, xlab = "Feed", ylab = "Weight", main = "Chicken Weights by Feed Type")

  1. What do these charts tell you? Does the box plot confirm you mean and median calculations? If yes, how so? Are there any outliers displayed in either chart? Confirm this using the five number summary for specific feed types and the IQR.

The charts tell me that my median and mean calculations are correct There appears to be one outlier in the box plot for horsebean

ch_df %>%
  group_by(feed) %>%
  summarize(min = min(weight, na.rm = TRUE), 
            q1 = quantile(weight, 0.25, na.rm = TRUE), 
            median = median(weight, na.rm = TRUE), 
            q3 = quantile(weight, 0.75, na.rm = TRUE), 
            max = max(weight, na.rm = TRUE), 
            iqr = IQR(weight, na.rm = TRUE))
## # A tibble: 9 × 7
##   feed        min    q1 median    q3   max   iqr
##   <chr>     <dbl> <dbl>  <dbl> <dbl> <dbl> <dbl>
## 1 casein      222  277.   325   356    379  78.8
## 2 horsebean   108  142.   160   174.   227  32  
## 3 linseed     148  205    236.  263.   309  57.8
## 4 meatmeal    206  280.   315   334.   380  54  
## 5 not sure    329  329    329   329    329   0  
## 6 soybean     158  225    249   268    327  43  
## 7 sunflower   318  328    340   366.   423  38.5
## 8 unknown     263  263    263   263    263   0  
## 9 <NA>        141  169    217   295    404 126

The five number summary confirms that there is an outlier of 227 in horsebean.

  1. Recreate the box plot above using ggplot and add x and y axis labels as well as a title. Describe any differences you notice about the two plots.
ggplot(data = ch_df, aes(x = feed, y = weight)) + 
  geom_boxplot() +
  labs(x = "Feed", y = "Weight", title = "Chicken Weights by Feed Type")
## Warning: Removed 15 rows containing non-finite values (`stat_boxplot()`).