Goodness of Fit
Lab 6 - Unit 5
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Exercise 1
Please work out in R by doing a chi-squared test on the treatment (X) and improvement (Y) columns in treatment.csv.
Data Exercise 1
e1 <- read.csv("treatment.csv")
e1Jawaban dan Penjelasan Exercise 1
H0 : kedua variabel independent
H1 : kedua variabel dependent
cont.e1 = table(e1$treatment, e1$improvement);cont.e1##
## improved not-improved
## not-treated 26 29
## treated 35 15
chisq.test(cont.e1,simulate.p.value = TRUE)##
## Pearson's Chi-squared test with simulated p-value (based on 2000
## replicates)
##
## data: cont.e1
## X-squared = 5.5569, df = NA, p-value = 0.03098
Berdasarkan hasil di atas, nilai p-value (0.02999) lebih kecil dari tingkat signifikan (0.05). Dengan demikian, H0 ditolak yang artinya kedua variabelnya (treatment dan improvement) dependent.
Exercise 2
Find out if the cyl and carb variables in
mtcars dataset are dependent or not.
Data Exercise 2
DT::datatable(mtcars)Jawaban dan Penjelasan Exercise 2
H0 : kedua variabel independent
H1 : kedua variabel dependent
cyl = mtcars$cyl
carb = mtcars$carb
chisq.test(cyl, carb)##
## Pearson's Chi-squared test
##
## data: cyl and carb
## X-squared = 24.389, df = 10, p-value = 0.006632
Berdasarkan hasil di atas, nilai p-value (0.006632) lebih kecil dari tingkat signifikan (0.05). Dengan demikian, H0 ditolak yang artinya kedua variabelnya (cly dan carb) dependent.
Exercise 3
256 visual artists were surveyed to find out their zodiac sign. The results were: Aries (29), Taurus (24), Gemini (22), Cancer (19), Leo (21), Virgo (18), Libra (19), Scorpio (20), Sagittarius (23), Capricorn (18), Aquarius (20), Pisces (23). Test the hypothesis that zodiac signs are evenly distributed across visual artists.
Data Exercise 3
n = 256
zodiac = c(29,24,22,19,21,18,19,20,23,18,20,23)
pert.zodiac = zodiac/n
expected = c(rep(256/12, 12))
e3 = data.frame(
"zodiak" = c('Aries', 'Taurus' , 'Gemini' , 'Cancer' , 'Leo' , 'Virgo' , 'Libra' , 'Scorpio', 'Sagittarius', 'Capricorn', 'Aquarius', 'Pisces'),
"observed" = zodiac,
'expected' = expected
)
e3Jawaban dan Penjelasan Exercise 3
H0 : semua zodiak terdistribusi dengan baik
H1 : terdapat zodiak
yang tidak terdistribusi dengan baik
chisq = sum((zodiac-expected)^2 / expected)
pchisq(q = chisq, df = 12-1, lower.tail=F)## [1] 0.9265414
Berdasarkan hasil di atas, nilai pchisq (0.9265414) lebih besar dari tingkat signifikan (0.05). Dengan demikian, H0 diterima yang artinya semua zodiak terdistribusi dengan baik.