Goals:
What does it mean to be proportional/power function?
Definition: \( y \) is proportional to \( x \) if there is some constant \( k \neq 0 \) such that \[ y=kx \] \( k \) is called the proportionality constant
Definition: \( y \) is a power function if it is proportional to a constant power of \( x \) \[ y=kx^p \]
Proportionality is just a power function with power one. Note \( p \) can be negative, if so we say inversely proportional.
Examples:
Exchange rate from Dollars to Euros \( E=0.76D \). So Euros are proportional to Dollars with proportionality constant 0.76
Area of a circle \( A= \pi r^2 \): A is proportional to the square of its radius \( r \) with constant of proportionality \( pi \)
Speed and travel time are inversely proportional because the faster you go, the shorter the time. As speed goes up, travel time goes down. \( r=\frac{D}{t}=Dt^{-1} \)
Example:
Circulation time of a mammal (the average time it takes for all the blood in the body to circulate once and return to the heart) is proportional to the fourth root of the body mass of the mammal.
Formula? \( T=kB^{1/4} \)
Know: Elephant of body mass 5230 kg has a circulation time of 148 sec.
\( 148 = k 5230^{1/4} \) then \( k=17.40349 \) so \( T=17.4B^{1/4} \)
So the circulation of a human with body mass 70 kg is \( T=17.4\cdot 70^{1/4}=50.33 \)
Recognizing data from a power function
Cool Fact: Given a power function \( y=kx^p \), can transform into a line \[ \ln y=\ln kx^p=\ln k + \ln x^p =\ln k + p\ln x \]
Rename: \( \ln y =Y \), \( \ln k =b \), \( \ln x = X \). So \( Y=b+pX \)
Example: The minimum annual gross income, \( g \), in throusands of dollars, needed for a home loan of $100,000 at various interest rates, \( r \)
| r | g |
|---|---|
| 8 | 31.447 |
| 9 | 34.484 |
| 10 | 37.611 |
| 11 | 40.814 |
| 12 | 44.084 |
rates = 8:12
income = c(31.447, 34.484, 37.611, 40.814, 44.084)
logrates = log(rates)
logincome = log(income)
| r | g | \( \ln r \) | \( \ln g \) |
|---|---|---|---|
| 8 | 31.447 | 2.079 | 3.448 |
| 9 | 34.484 | 2.197 | 3.540 |
| 10 | 37.611 | 2.303 | 3.627 |
| 11 | 40.814 | 2.398 | 3.709 |
| 12 | 44.084 | 2.485 | 3.79 |
plotPoints(logincome ~ logrates)
plotPoints(logincome ~ logrates)
plotFun(0.833 * x + 1.712 ~ x, add = TRUE)
-Then \( p=m=0.833 \) and \( k=e^b=e^{1.712}=5.54 \)