Many college courses conclude by giving students the opportunity to evaluate the course and the instructor anonymously. However, the use of these student evaluations as an indicator of course quality and teaching effectiveness is often criticized because these measures may reflect the influence of non-teaching related characteristics, such as the physical appearance of the instructor. The article titled, “Beauty in the classroom: instructors’ pulchritude and putative pedagogical productivity” (Hamermesh and Parker, 2005) found that instructors who are viewed to be better looking receive higher instructional ratings. (Daniel S. Hamermesh, Amy Parker, Beauty in the classroom: instructors pulchritude and putative pedagogical productivity, Economics of Education Review, Volume 24, Issue 4, August 2005, Pages 369-376, ISSN 0272-7757, 10.1016/j.econedurev.2004.07.013. http://www.sciencedirect.com/science/article/pii/S0272775704001165.)
In this lab we will analyze the data from this study in order to learn what goes into a positive professor evaluation.
The data were gathered from end of semester student evaluations for a large sample of professors from the University of Texas at Austin. In addition, six students rated the professors’ physical appearance. (This is aslightly modified version of the original data set that was released as part of the replication data for Data Analysis Using Regression and Multilevel/Hierarchical Models (Gelman and Hill, 2007).) The result is a data frame where each row contains a different course and columns represent variables about the courses and professors.
load("more/evals.RData")
variable | description |
---|---|
score |
average professor evaluation score: (1) very unsatisfactory - (5) excellent. |
rank |
rank of professor: teaching, tenure track, tenured. |
ethnicity |
ethnicity of professor: not minority, minority. |
gender |
gender of professor: female, male. |
language |
language of school where professor received education: english or non-english. |
age |
age of professor. |
cls_perc_eval |
percent of students in class who completed evaluation. |
cls_did_eval |
number of students in class who completed evaluation. |
cls_students |
total number of students in class. |
cls_level |
class level: lower, upper. |
cls_profs |
number of professors teaching sections in course in sample: single, multiple. |
cls_credits |
number of credits of class: one credit (lab, PE, etc.), multi credit. |
bty_f1lower |
beauty rating of professor from lower level female: (1) lowest - (10) highest. |
bty_f1upper |
beauty rating of professor from upper level female: (1) lowest - (10) highest. |
bty_f2upper |
beauty rating of professor from second upper level female: (1) lowest - (10) highest. |
bty_m1lower |
beauty rating of professor from lower level male: (1) lowest - (10) highest. |
bty_m1upper |
beauty rating of professor from upper level male: (1) lowest - (10) highest. |
bty_m2upper |
beauty rating of professor from second upper level male: (1) lowest - (10) highest. |
bty_avg |
average beauty rating of professor. |
pic_outfit |
outfit of professor in picture: not formal, formal. |
pic_color |
color of professor’s picture: color, black & white. |
Answer This is an observational study. No experiment were set-up. The observations were gathered by end of class evaluations and questionair answered by 6 students pertaining on the beauty assessment of the professors.
Because this is not an experiment, we cannot conclude casual relationship. We would need to rephrase the question as follows
Question: Does beauty impact a professor evaluation or is the difference due to sampling variation?
score
. Is the distribution skewed? What does that tell you about how students rate courses? Is this what you expected to see? Why, or why not?Answer
hist(evals$score)
From the histogram, we can see that the distribution of ‘score’ is skewed to the left, with the majority of the observation with score of between 4 and 5. This is as expected, most students will provide feeback with positive evaluation (4 or 5).
score
, select two other variables and describe their relationship using an appropriate visualization (scatterplot, side-by-side boxplots, or mosaic plot).Answer We will consider the following variables: cls_perc_eval and cls_level. We will plot percentage of sutdent that complete evaluation dependent on the class level.
plot(evals$cls_perc_eval ~ evals$cls_level)
The percentage of student completing the evaluation has less variability for upper level class (since the box plot is smaller) than for lower. There is no clear apparent difference for the median. There is a marked difference for the lower whiskers. For upper level class, the lower whisker ends higher with outliers. There are no outiers for lower class level.
The fundamental phenomenon suggested by the study is that better looking teachers are evaluated more favorably. Let’s create a scatterplot to see if this appears to be the case:
plot(evals$score ~ evals$bty_avg)
Before we draw conclusions about the trend, compare the number of observations in the data frame with the approximate number of points on the scatterplot. Is anything awry?
nrow(evals)
## [1] 463
summary(evals)
## score rank ethnicity gender
## Min. :2.300 teaching :102 minority : 64 female:195
## 1st Qu.:3.800 tenure track:108 not minority:399 male :268
## Median :4.300 tenured :253
## Mean :4.175
## 3rd Qu.:4.600
## Max. :5.000
## language age cls_perc_eval cls_did_eval
## english :435 Min. :29.00 Min. : 10.42 Min. : 5.00
## non-english: 28 1st Qu.:42.00 1st Qu.: 62.70 1st Qu.: 15.00
## Median :48.00 Median : 76.92 Median : 23.00
## Mean :48.37 Mean : 74.43 Mean : 36.62
## 3rd Qu.:57.00 3rd Qu.: 87.25 3rd Qu.: 40.00
## Max. :73.00 Max. :100.00 Max. :380.00
## cls_students cls_level cls_profs cls_credits
## Min. : 8.00 lower:157 multiple:306 multi credit:436
## 1st Qu.: 19.00 upper:306 single :157 one credit : 27
## Median : 29.00
## Mean : 55.18
## 3rd Qu.: 60.00
## Max. :581.00
## bty_f1lower bty_f1upper bty_f2upper bty_m1lower
## Min. :1.000 Min. :1.000 Min. : 1.000 Min. :1.000
## 1st Qu.:2.000 1st Qu.:4.000 1st Qu.: 4.000 1st Qu.:2.000
## Median :4.000 Median :5.000 Median : 5.000 Median :3.000
## Mean :3.963 Mean :5.019 Mean : 5.214 Mean :3.413
## 3rd Qu.:5.000 3rd Qu.:7.000 3rd Qu.: 6.000 3rd Qu.:5.000
## Max. :8.000 Max. :9.000 Max. :10.000 Max. :7.000
## bty_m1upper bty_m2upper bty_avg pic_outfit
## Min. :1.000 Min. :1.000 Min. :1.667 formal : 77
## 1st Qu.:3.000 1st Qu.:4.000 1st Qu.:3.167 not formal:386
## Median :4.000 Median :5.000 Median :4.333
## Mean :4.147 Mean :4.752 Mean :4.418
## 3rd Qu.:5.000 3rd Qu.:6.000 3rd Qu.:5.500
## Max. :9.000 Max. :9.000 Max. :8.167
## pic_color
## black&white: 78
## color :385
##
##
##
##
The dataframe evals has total 463 observations and summary says that there is no missing observation which would represent ‘NA’. So the scatter plot should have 463 points. But the scatter plot has only 250 points. Thatst he awry.
jitter()
on the \(y\)- or the \(x\)-coordinate. (Use ?jitter
to learn more.) What was misleading about the initial scatterplot?Answer
Add a small amount of noise to the score by using jitter function
plot(jitter(evals$score) ~ evals$bty_avg)
May points have the same values for (x,y). So they could not be differenciated on the scatter plot. As a small amount of noise is added on the score variable(y),the points can be differenciated. So instead of 250 points, all 463 points are visible.
m_bty
to predict average professor score by average beauty rating and add the line to your plot using abline(m_bty)
. Write out the equation for the linear model and interpret the slope. Is average beauty score a statistically significant predictor? Does it appear to be a practically significant predictor?Answer
m_bty<- lm(score ~ bty_avg, data = evals)
plot(jitter(evals$score) ~ evals$bty_avg)
abline(m_bty)
summary(m_bty)
##
## Call:
## lm(formula = score ~ bty_avg, data = evals)
##
## Residuals:
## Min 1Q Median 3Q Max
## -1.9246 -0.3690 0.1420 0.3977 0.9309
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 3.88034 0.07614 50.96 < 2e-16 ***
## bty_avg 0.06664 0.01629 4.09 5.08e-05 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 0.5348 on 461 degrees of freedom
## Multiple R-squared: 0.03502, Adjusted R-squared: 0.03293
## F-statistic: 16.73 on 1 and 461 DF, p-value: 5.083e-05
\(\hat { y } ={ b }_{ 0 }+{ b }_{ 1 }x\)
\(\hat { y } =3.88034+0.06664\times bty\_ avg\)
slope of the line is 0.06664. That means when average beauty of the professor goes up by 1, the score goes up by 0.6664.
p-value is 5.083e-05 which is close to zero. It may not be a practically significant predictor of evaluation score though since for every 1 point increase in bty_ave, the model only predicts an increase of 0.06664 which barely changes the evaluation score.
Answer
plot(m_bty$residuals ~ evals$bty_avg)
abline(h = 0, lty = 4) # adds a horizontal dashed line at y = 0
#Historgream
hist(m_bty$residuals)
# normal probability plot of the residuals
qqnorm(m_bty$residuals)
qqline(m_bty$residuals)
Conditions for the least squares line
Linearity: The data show a slightly linear and it is positive linearity.
Nearly Normal residuals: From the Histogram, the residuals show a slightly left skewed distribution. The normal probability plot of the residuals shows that the points do not follow the line for upper quadriles.
Constant Variability: From the residual plot, we can observe that there seems to have constant variability.
Independent observations: We do not have much information on how the sample was taken. We can assume indenpendence of the observations.
The data set contains several variables on the beauty score of the professor: individual ratings from each of the six students who were asked to score the physical appearance of the professors and the average of these six scores. Let’s take a look at the relationship between one of these scores and the average beauty score.
plot(evals$bty_avg ~ evals$bty_f1lower)
cor(evals$bty_avg, evals$bty_f1lower)
As expected the relationship is quite strong - after all, the average score is calculated using the individual scores. We can actually take a look at the relationships between all beauty variables (columns 13 through 19) using the following command:
plot(evals[,13:19])
These variables are collinear (correlated), and adding more than one of these variables to the model would not add much value to the model. In this application and with these highly-correlated predictors, it is reasonable to use the average beauty score as the single representative of these variables.
In order to see if beauty is still a significant predictor of professor score after we’ve accounted for the gender of the professor, we can add the gender term into the model.
m_bty_gen <- lm(score ~ bty_avg + gender, data = evals)
summary(m_bty_gen)
##
## Call:
## lm(formula = score ~ bty_avg + gender, data = evals)
##
## Residuals:
## Min 1Q Median 3Q Max
## -1.8305 -0.3625 0.1055 0.4213 0.9314
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 3.74734 0.08466 44.266 < 2e-16 ***
## bty_avg 0.07416 0.01625 4.563 6.48e-06 ***
## gendermale 0.17239 0.05022 3.433 0.000652 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 0.5287 on 460 degrees of freedom
## Multiple R-squared: 0.05912, Adjusted R-squared: 0.05503
## F-statistic: 14.45 on 2 and 460 DF, p-value: 8.177e-07
Answer
# Normal Probability Plot
qqnorm(m_bty_gen$residuals)
qqline(m_bty_gen$residuals)
# residual plot against each predictor variable
plot(m_bty_gen$residuals ~ evals$bty_avg)
abline(h = 0, lty = 4) # adds a horizontal dashed line at y = 0
plot(m_bty_gen$residuals ~ evals$gender)
abline(h = 0, lty = 4) # adds a horizontal dashed line at y = 0
#Resiual vs Fitted, Normal Probability Plot, Scale-Location, Residual vs Leverage
plot(m_bty_gen)
#Historgream
hist(m_bty_gen$residuals)
# Checking linearlidity
plot(jitter(evals$score) ~ evals$bty_avg)
plot(evals$score ~ evals$gender)
The histogram of residuals suggests that the residuals distribution is slightly skewed to the left.
The residuals do not follow the lines for upper quadriles in the Normal Probability Plot for residuals, .
Residuals vs Fitted, show that it appears to be constant variability for residuals. But as was established in the previous exercises, there is a linear relationship between beauty average and teaching evaluation score.
bty_avg
still a significant predictor of score
? Has the addition of gender
to the model changed the parameter estimate for bty_avg
?Yes it is. In fact, gender made beauty average even more significant as the p-value computed is even smaller (6.48e-06 < 5.08e-05) now compared to a model where beauty average was the only variable.
Note that the estimate for gender
is now called gendermale
. You’ll see this name change whenever you introduce a categorical variable. The reason is that R recodes gender
from having the values of female
and male
to being an indicator variable called gendermale
that takes a value of \(0\) for females and a value of \(1\) for males. (Such variables are often referred to as “dummy” variables.)
As a result, for females, the parameter estimate is multiplied by zero, leaving the intercept and slope form familiar from simple regression.
\[ \begin{aligned} \widehat{score} &= \hat{\beta}_0 + \hat{\beta}_1 \times bty\_avg + \hat{\beta}_2 \times (0) \\ &= \hat{\beta}_0 + \hat{\beta}_1 \times bty\_avg\end{aligned} \]
We can plot this line and the line corresponding to males with the following custom function.
multiLines(m_bty_gen)
\(\hat { score } =\quad 3.74734\quad +\quad 0.07416\quad ×\quad beauty\_ avg\quad +\quad 0.17239\quad ×\quad gender\_ male\)
For gender = Male, we will evaluate the equation with gender_male = 1. In case, of female gender, we will substitute a 0.
\(\hat { score } =\quad 3.74734\quad +\quad 0.07416\quad ×\quad beauty\_ avg\quad +\quad 0.17239\)
Male professor will have a evaluation score higher by 0.17239 all other things being equal.
The decision to call the indicator variable gendermale
instead ofgenderfemale
has no deeper meaning. R simply codes the category that comes first alphabetically as a \(0\). (You can change the reference level of a categorical variable, which is the level that is coded as a 0, using therelevel
function. Use ?relevel
to learn more.)
m_bty_rank
with gender
removed and rank
added in. How does R appear to handle categorical variables that have more than two levels? Note that the rank variable has three levels: teaching
, tenure track
, tenured
.Answer
m_bty_rank <- lm(score ~ bty_avg + rank, data = evals)
summary(m_bty_rank)
##
## Call:
## lm(formula = score ~ bty_avg + rank, data = evals)
##
## Residuals:
## Min 1Q Median 3Q Max
## -1.8713 -0.3642 0.1489 0.4103 0.9525
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 3.98155 0.09078 43.860 < 2e-16 ***
## bty_avg 0.06783 0.01655 4.098 4.92e-05 ***
## ranktenure track -0.16070 0.07395 -2.173 0.0303 *
## ranktenured -0.12623 0.06266 -2.014 0.0445 *
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 0.5328 on 459 degrees of freedom
## Multiple R-squared: 0.04652, Adjusted R-squared: 0.04029
## F-statistic: 7.465 on 3 and 459 DF, p-value: 6.88e-05
For variable with more than 2 levels, it appears to handle it considerering them 2 different variables.
The interpretation of the coefficients in multiple regression is slightly different from that of simple regression. The estimate for bty_avg
reflects how much higher a group of professors is expected to score if they have a beauty rating that is one point higher while holding all other variables constant. In this case, that translates into considering only professors of the same rank with bty_avg
scores that are one point apart.
We will start with a full model that predicts professor score based on rank, ethnicity, gender, language of the university where they got their degree, age, proportion of students that filled out evaluations, class size, course level, number of professors, number of credits, average beauty rating, outfit, and picture color.
Answer :
The “number of professors” (cls_profs) as the variable to have the least assoication with the professor’s evaluation score.
Let’s run the model…
m_full <- lm(score ~ rank + ethnicity + gender + language + age + cls_perc_eval
+ cls_students + cls_level + cls_profs + cls_credits + bty_avg
+ pic_outfit + pic_color, data = evals)
summary(m_full)
Answer
The “number of professors” (cls_profs) as the variable to have the least assoication with the professor’s evaluation score. That has the maximum p-value(0.77806)
Answer All other things being equal, Evaluation for professor that not minority tends to be 0.1234929 higher.
Answer
m_full_1 <- lm(score ~ rank + ethnicity + gender + language + age + cls_perc_eval
+ cls_students + cls_level + cls_credits + bty_avg
+ pic_outfit + pic_color, data = evals)
summary(m_full_1)
##
## Call:
## lm(formula = score ~ rank + ethnicity + gender + language + age +
## cls_perc_eval + cls_students + cls_level + cls_credits +
## bty_avg + pic_outfit + pic_color, data = evals)
##
## Residuals:
## Min 1Q Median 3Q Max
## -1.7836 -0.3257 0.0859 0.3513 0.9551
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 4.0872523 0.2888562 14.150 < 2e-16 ***
## ranktenure track -0.1476746 0.0819824 -1.801 0.072327 .
## ranktenured -0.0973829 0.0662614 -1.470 0.142349
## ethnicitynot minority 0.1274458 0.0772887 1.649 0.099856 .
## gendermale 0.2101231 0.0516873 4.065 5.66e-05 ***
## languagenon-english -0.2282894 0.1111305 -2.054 0.040530 *
## age -0.0089992 0.0031326 -2.873 0.004262 **
## cls_perc_eval 0.0052888 0.0015317 3.453 0.000607 ***
## cls_students 0.0004687 0.0003737 1.254 0.210384
## cls_levelupper 0.0606374 0.0575010 1.055 0.292200
## cls_creditsone credit 0.5061196 0.1149163 4.404 1.33e-05 ***
## bty_avg 0.0398629 0.0174780 2.281 0.023032 *
## pic_outfitnot formal -0.1083227 0.0721711 -1.501 0.134080
## pic_colorcolor -0.2190527 0.0711469 -3.079 0.002205 **
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 0.4974 on 449 degrees of freedom
## Multiple R-squared: 0.187, Adjusted R-squared: 0.1634
## F-statistic: 7.943 on 13 and 449 DF, p-value: 2.336e-14
The coefficients and significance changed slightly. Since the values changed, the drop variable was slightly collinear with the other explanatory variables.
m_full_best <- lm(score ~ ethnicity + gender + language + age + cls_perc_eval
+ cls_credits + bty_avg + pic_color, data = evals)
summary(m_full_best)
##
## Call:
## lm(formula = score ~ ethnicity + gender + language + age + cls_perc_eval +
## cls_credits + bty_avg + pic_color, data = evals)
##
## Residuals:
## Min 1Q Median 3Q Max
## -1.85320 -0.32394 0.09984 0.37930 0.93610
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 3.771922 0.232053 16.255 < 2e-16 ***
## ethnicitynot minority 0.167872 0.075275 2.230 0.02623 *
## gendermale 0.207112 0.050135 4.131 4.30e-05 ***
## languagenon-english -0.206178 0.103639 -1.989 0.04726 *
## age -0.006046 0.002612 -2.315 0.02108 *
## cls_perc_eval 0.004656 0.001435 3.244 0.00127 **
## cls_creditsone credit 0.505306 0.104119 4.853 1.67e-06 ***
## bty_avg 0.051069 0.016934 3.016 0.00271 **
## pic_colorcolor -0.190579 0.067351 -2.830 0.00487 **
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 0.4992 on 454 degrees of freedom
## Multiple R-squared: 0.1722, Adjusted R-squared: 0.1576
## F-statistic: 11.8 on 8 and 454 DF, p-value: 2.58e-15
\(\hat { score } =\quad \hat { { \beta }_{ 0 } } \quad +\quad \hat { { \beta }_{ 1 } } \quad ×\quad ethnicitynot\_ minority\quad +\quad \hat { { \beta }_{ 2 } } ×gendermale\quad +\quad \hat { { \beta }_{ 3\quad } } ×\quad languagenon-english+\quad \hat { { \beta }_{ 4 } } ×\quad age\quad +\quad \hat { { \beta }_{ 5 } } ×\quad cls\_ perc\_ eval\quad +\quad \hat { { \beta }_{ 6 } } ×\quad cls\_ reditsone\_ credit\quad +\quad \hat { { \beta }_{ 7 } } ×\quad bty\_ avg\quad +\quad \hat { { \beta }_{ 8 } } ×\quad pic\_ colorcolor\)
# Normal Probability Plot
qqnorm(m_full_best$residuals)
qqline(m_full_best$residuals)
# 4 plots: Resiual vs Fitted, Normal Probability Plot, Scale-Location, Residual vs Leverage
plot(m_full_best)
#Historgream
hist(m_full_best$residuals)
# Checking linearlidity
plot(jitter(evals$score) ~ evals$bty_avg)
plot(jitter(evals$score) ~ evals$gender)
plot(jitter(evals$score) ~ evals$ethnicity)
plot(jitter(evals$score) ~ evals$language
)
plot(jitter(evals$score) ~ evals$age)
plot(jitter(evals$score) ~ evals$cls_perc_eval)
plot(jitter(evals$score) ~ evals$cls_credits)
plot(jitter(evals$score) ~ evals$pic_color)
Answer
No. Even if the course is being taught by the same professor, Class courses are independent of each other so evaluation scores from one course is indpendent of the other
Answer
Based on the coefficients Professor would be younger male teaching one credit class, he would not belong to a minority group, he would have received this degree from a universtity where english is the language. The professor would have a black and white picture and who have been rated beautifull.
Answer
No, this was not conducted as an experiment but based on a sample in a given university. As cultural value changes, these results may be different in other university or in a different time frame.
This is a product of OpenIntro that is released under a Creative Commons Attribution-ShareAlike 3.0 Unported. This lab was written by Mine Çetinkaya-Rundel and Andrew Bray.